Aptitude Mock Test for Practice 2
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We had complied the most asked aptitude question and answers with their explanation in this mock test.
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Question 1 of 10
1. Question
Can you find the approximate value for the below equation
110.99 / 121.99 * 108.01 – 115.01 + 104.01
Correct
Answer 87
Explanation:Given Question is 110.99 / 121.99 * 108.01 – 115.01 + 104.01
when we apply BODMAS RULE and round it off, we get => ( 111 / 122 ) * 108 – 115 + 104 = 1*108115+104 = 87Incorrect
Answer 87
Explanation:Given Question is 110.99 / 121.99 * 108.01 – 115.01 + 104.01
when we apply BODMAS RULE and round it off, we get => ( 111 / 122 ) * 108 – 115 + 104 = 1*108115+104 = 87 
Question 2 of 10
2. Question
Peter bought a laptop for Rs. 24,700, which he later sold to John for Rs. 26000. Find the profit percentage.
Correct
Answer 5%
Explanation:S.P = 26000 and C.P = 24700.
Profit = S.P – C.P = 26000 – 24700 = 1300
Profit percentage = (Profit /C.P) x 100 = (1300/26000) x 100 = 100 / 20 = 5 %Incorrect
Answer 5%
Explanation:S.P = 26000 and C.P = 24700.
Profit = S.P – C.P = 26000 – 24700 = 1300
Profit percentage = (Profit /C.P) x 100 = (1300/26000) x 100 = 100 / 20 = 5 % 
Question 3 of 10
3. Question
A motorboat went the river for 14 km and then up the river for 9 km. It took a total of 5 hrs the entire journey. Find the speed of the river flow if the speed of the boat in still water is 5 km/hr
Correct
Answer 2 km/hr
Explanation:Let the speed of the stream be x kmph
Then Upward speed = 5x kmph and Downstream = 5+x kmph
14/(5+x) + (9/(5x)) = 5
14x + 115 + 9x = 5(25x^{2})
5x + 115 = 125 – 5x^{2}
5x = 10 – 5x^{2}
x = 2 x^{2}
x^{2}– x 2 = 0
(x + 1)(x – 2) = 0
x = 1, 2 (x = 1 is not possible)
So, x = 2 km/hrIncorrect
Answer 2 km/hr
Explanation:Let the speed of the stream be x kmph
Then Upward speed = 5x kmph and Downstream = 5+x kmph
14/(5+x) + (9/(5x)) = 5
14x + 115 + 9x = 5(25x^{2})
5x + 115 = 125 – 5x^{2}
5x = 10 – 5x^{2}
x = 2 x^{2}
x^{2}– x 2 = 0
(x + 1)(x – 2) = 0
x = 1, 2 (x = 1 is not possible)
So, x = 2 km/hr 
Question 4 of 10
4. Question
A train travels from City X to City Y at a speed of 44 kmph, while on its return journey the train was travelling at speed of 77 kmph. Find the average speed of the train.
Correct
Answer 56
Explanation:Let x be the speed of the train while going from City X to Y.
Let y be the speed of the train while going from City Y to X.Average speed of the train is given by = 2xy / (x+y)
Average speed = (2 x 44 x 77) / (44 + 77 )
Average speed = 56Incorrect
Answer 56
Explanation:Let x be the speed of the train while going from City X to Y.
Let y be the speed of the train while going from City Y to X.Average speed of the train is given by = 2xy / (x+y)
Average speed = (2 x 44 x 77) / (44 + 77 )
Average speed = 56 
Question 5 of 10
5. Question
Find the next number in the the below series
26, 45, 65, 86, _____
Correct
Answer 108
Explanation:In the given series, 26, 45, 65, 86 ,Consecutive numbers increase by 19 ,20 ,21.
Following the same pattern, the next number should increase by 22.
When we add 22 to the last number (i.e 86) we get 22+86=108
Incorrect
Answer 108
Explanation:In the given series, 26, 45, 65, 86 ,Consecutive numbers increase by 19 ,20 ,21.
Following the same pattern, the next number should increase by 22.
When we add 22 to the last number (i.e 86) we get 22+86=108

Question 6 of 10
6. Question
What least number must be subtracted from 13601, so that the remainder is divisible by 87 ?
Correct
Answer 29
Explanation:13601 = 87 x 156 + 29
Here 29 is the remainder.Incorrect
Answer 29
Explanation:13601 = 87 x 156 + 29
Here 29 is the remainder. 
Question 7 of 10
7. Question
Can you find the approximate value for the below equation
Correct
Answer 31
Explanation:Given Question is 15.99 * 32.99 / 21.01 + 30.01 – 23.99
when we apply BODMAS RULE and round it off, we get => 16 * ( 33 / 21 ) + 30 – 24 = 16 * 2+ 30 – 24 = 31Incorrect
Answer 31
Explanation:Given Question is 15.99 * 32.99 / 21.01 + 30.01 – 23.99
when we apply BODMAS RULE and round it off, we get => 16 * ( 33 / 21 ) + 30 – 24 = 16 * 2+ 30 – 24 = 31 
Question 8 of 10
8. Question
Can you find the approximate value for the below equation
Correct
Answer 93
Explanation:Given Question is 91.01 * 111.01 / 97.99 – 108.99 + 99.01
when we apply BODMAS RULE and round it off, we get => 91 * ( 111 / 98 ) – 109 + 99 = 91 * 1 109 + 99 = 93Incorrect
Answer 93
Explanation:Given Question is 91.01 * 111.01 / 97.99 – 108.99 + 99.01
when we apply BODMAS RULE and round it off, we get => 91 * ( 111 / 98 ) – 109 + 99 = 91 * 1 109 + 99 = 93 
Question 9 of 10
9. Question
Can you find the answer for the below equation
66 / 314 * 301 – 308 + 297
Correct
Answer 52.27
Explanation:Given Question is 66 / 314 * 301 – 308 + 297
when we apply BODMAS RULE to the above question, we get (Bracket Of Division) ( 66 / 314 ) * 301 – 308 + 297 = 0.21*301308+297 = 52.27Incorrect
Answer 52.27
Explanation:Given Question is 66 / 314 * 301 – 308 + 297
when we apply BODMAS RULE to the above question, we get (Bracket Of Division) ( 66 / 314 ) * 301 – 308 + 297 = 0.21*301308+297 = 52.27 
Question 10 of 10
10. Question
Evaluate the expression: 2 + 5 * 6 – 7 * 8 / 4 + 6
Correct
Answer 24
Explanation:Given Question is 2 + 5 * 6 – 7 * 8 / 4 + 6
when we apply BODMAS RULE to the above question, we get
2 + 5 * 6 – 7 * (8 / 4) + 6
= 2 + (5 * 6) – (7 * 2) + 6
= 2 + 30 – 14 + 6
= 38 – 14
= 24Incorrect
Answer 24
Explanation:Given Question is 2 + 5 * 6 – 7 * 8 / 4 + 6
when we apply BODMAS RULE to the above question, we get
2 + 5 * 6 – 7 * (8 / 4) + 6
= 2 + (5 * 6) – (7 * 2) + 6
= 2 + 30 – 14 + 6
= 38 – 14
= 24