Aptitude Mock Test For Practise 1
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We tried to compile the most important question which was asked in the Accenture test. In this quiz, we added Accenture Aptitude Questions and Answers with Explanation
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Question 1 of 10
1. Question
Evaluate the expression: 2 + 5 * 6 – 7 * 8 / 4 + 6
Correct
Answer 24
Explanation:
Given Question is 2 + 5 * 6 – 7 * 8 / 4 + 6
when we apply BODMAS RULE to the above question, we get
2 + 5 * 6 – 7 * (8 / 4) + 6
= 2 + (5 * 6) – (7 * 2) + 6
= 2 + 30 – 14 + 6
= 38 – 14
= 24Incorrect
Answer 24
Explanation:
Given Question is 2 + 5 * 6 – 7 * 8 / 4 + 6
when we apply BODMAS RULE to the above question, we get
2 + 5 * 6 – 7 * (8 / 4) + 6
= 2 + (5 * 6) – (7 * 2) + 6
= 2 + 30 – 14 + 6
= 38 – 14
= 24 
Question 2 of 10
2. Question
There were 12 students in a particular Class. The class teacher knows the overall height of all the students in the class is 1400. Can you find the average height of students in the class?
Correct
Answer 116.67
Explanation:Use the below formula to find the average height of students in the class Average Height = ( Total Height of all students in the Class / Total Number of Students) Average Height = ( 1400/12) = 116.67Incorrect
Answer 116.67
Explanation:Use the below formula to find the average height of students in the class Average Height = ( Total Height of all students in the Class / Total Number of Students) Average Height = ( 1400/12) = 116.67 
Question 3 of 10
3. Question
Can you find the approximate value for the following expression:
29.8% of 260 + 60.01% of 510 − 103.57 = ?
Correct
Answer 280
Explanation:Given
29.8% of 260 + 60.01% of 510 − 103.57 = ?Rounding off the given Expression we get,
= ( 30 / 100 ) * 260 + ( 60 / 100 ) * 510 – ( 104 )
= 78 + 306 – 104
= 384 – 104
= 280Incorrect
Answer 280
Explanation:Given
29.8% of 260 + 60.01% of 510 − 103.57 = ?Rounding off the given Expression we get,
= ( 30 / 100 ) * 260 + ( 60 / 100 ) * 510 – ( 104 )
= 78 + 306 – 104
= 384 – 104
= 280 
Question 4 of 10
4. Question
The length of the side of a square is represented by x+2. The length of the side of an equilateral triangle is 2x. If the square and the equilateral triangle have equal perimeter, then the value of x is _______
Correct
Answer 4
Explanation:Since the side of the square is x + 2, its perimeter = 4 * side = 4 (x + 2) = 4x + 8
Since the side of the equilateral triangle is 2x, its perimeter = 3 * side = 3 * 2x = 6x
Also, the perimeters of both are equal. (i.e.) 4x + 8 = 6x (i.e.) 2x = 8 => x = 4Incorrect
Answer 4
Explanation:Since the side of the square is x + 2, its perimeter = 4 * side = 4 (x + 2) = 4x + 8
Since the side of the equilateral triangle is 2x, its perimeter = 3 * side = 3 * 2x = 6x
Also, the perimeters of both are equal. (i.e.) 4x + 8 = 6x (i.e.) 2x = 8 => x = 4 
Question 5 of 10
5. Question
Find the approximate value
24% of 650 – ? % of 123. 68 = 78.2Correct
Answer 63
Explanation:Given expression is:
24% of 650 – ? % 123. 68 = 78.2
=> ( 24 / 100) * 650 – [(X / 100) * 123.68] = 78.2 ( rounding off we get)
=> 156 – (X / 100) * 124 = 78
=> 156 – 78 = (X /100) * 124
=> 78 = (X /100) * 124
=> X = (100 * 78) / 124
=> X = 62.90
=> X = 63 approximately.Incorrect
Answer 63
Explanation:Given expression is:
24% of 650 – ? % 123. 68 = 78.2
=> ( 24 / 100) * 650 – [(X / 100) * 123.68] = 78.2 ( rounding off we get)
=> 156 – (X / 100) * 124 = 78
=> 156 – 78 = (X /100) * 124
=> 78 = (X /100) * 124
=> X = (100 * 78) / 124
=> X = 62.90
=> X = 63 approximately. 
Question 6 of 10
6. Question
A farmer decides to plough a Rectangle shaped field whose land measures 45x37m. To plough the field using tractor, the driver charges Rs.44 per Sq.m. Find the overall cost to the farmer?
Correct
Answer Rs. 73260
Explanation:Given Length = 45m & Breadth = 37m
Area of Rectangle = Length x Breadth => 45 x =37 = 1665
Price = Area x Cost Per Sq.m = 1665 x 44 = 73260Incorrect
Answer Rs. 73260
Explanation:Given Length = 45m & Breadth = 37m
Area of Rectangle = Length x Breadth => 45 x =37 = 1665
Price = Area x Cost Per Sq.m = 1665 x 44 = 73260 
Question 7 of 10
7. Question
Which of the following expressions is equivalent to sin 6x :
Correct
Answer sin 2x cos 4x + cos 2x sin 4x
Explanation:sin (A + B) = sin A cos B + cos A sin B
Let A = 2x and B = 4x
Sin (6x) = sin (2x + 4x) = sin (2x) cos (4x) + cos (2x) sin (4x)Incorrect
Answer sin 2x cos 4x + cos 2x sin 4x
Explanation:sin (A + B) = sin A cos B + cos A sin B
Let A = 2x and B = 4x
Sin (6x) = sin (2x + 4x) = sin (2x) cos (4x) + cos (2x) sin (4x) 
Question 8 of 10
8. Question
What least number must be subtracted from 13601, so that the remainder is divisible by 87 ?
Correct
Answer 29
Explanation:13601 = 87 x 156 + 29
Here 29 is the remainder.Incorrect
Answer 29
Explanation:13601 = 87 x 156 + 29
Here 29 is the remainder. 
Question 9 of 10
9. Question
Two numbers are in the ratio 3 : 5. If 9 is subtracted from each, the new numbers are in the ratio 12 : 23. The smaller number is:
Correct
Answer 33
Explanation:Let the numbers be 3x and 5x
Then (3x9)/(5x9) = 12/23 => 23(3x9)=12(5x9) => 9x = 99 => x = 11
Therefore the smaller number is 3x = 3 x 11 = 33Incorrect
Answer 33
Explanation:Let the numbers be 3x and 5x
Then (3x9)/(5x9) = 12/23 => 23(3x9)=12(5x9) => 9x = 99 => x = 11
Therefore the smaller number is 3x = 3 x 11 = 33 
Question 10 of 10
10. Question
A train travels from City X to City Y at a speed of 44 kmph, while on its return journey the train was travelling at speed of 77 kmph. Find the average speed of the train.
Correct
Answer 56
Explanation:Let x be the speed of the train while going from City X to Y.
Let y be the speed of the train while going from City Y to X.Average speed of the train is given by = 2xy / (x+y)
Average speed = (2 x 44 x 77) / (44 + 77 )
Average speed = 56Incorrect
Answer 56
Explanation:Let x be the speed of the train while going from City X to Y.
Let y be the speed of the train while going from City Y to X.Average speed of the train is given by = 2xy / (x+y)
Average speed = (2 x 44 x 77) / (44 + 77 )
Average speed = 56